Question

Тело массой 2 кг падает с высоты 10 м.и углубляется в песок на глубину 0,5м Определить среднию силу сопротивления песка

Answer 1

Дано m=2 кг  H=10 м      h=0,5 м  Fс- ?

m*g*(H+h)+Aс=0
Аc=-Fс*h

Fс=m*g*(H+h)/h=2*10*10,5/0,5=40*10,5=420 Н

Answer 2

Calculation of Average Resistance Force

To determine the average resistance force exerted by the sand when a 2 kg body falls from a height of 10 m and sinks into the sand to a depth of 0.5 m, we can use the principle of work and energy.

The work done by the resistance force of the sand can be calculated as the difference in potential energy before and after the fall:

Work done by resistance force = Change in potential energy

The potential energy before the fall is given by the formula:

Potential energy before = mgh

Where: - m is the mass of the body (2 kg) - g is the acceleration due to gravity (approximately 9.8 m/s^2) - h is the height from which the body falls (10 m)

Substituting the values, we get:

Potential energy before = 2 kg * 9.8 m/s^2 * 10 m = 196 J

The potential energy after the fall is given by the formula:

Potential energy after = mgh'

Where: - h' is the depth to which the body sinks into the sand (0.5 m)

Substituting the values, we get:

Potential energy after = 2 kg * 9.8 m/s^2 * 0.5 m = 9.8 J

The work done by the resistance force is the difference between the potential energies:

Work done by resistance force = Potential energy before - Potential energy after = 196 J - 9.8 J = 186.2 J

The average resistance force can be calculated by dividing the work done by the distance over which the force is applied. In this case, the distance is the depth to which the body sinks into the sand (0.5 m).

Average resistance force = Work done by resistance force / Distance = 186.2 J / 0.5 m = 372.4 N

Therefore, the average resistance force exerted by the sand is approximately 372.4 N.