Question

На малый поршень действует сила 500H, и он сдвигается на 0.1 м .Прессом поднимает массу 2000 кг . Кпд 0.8 . на сколько метров сдвинется большой поршень варианты 0.5,1,0.02,0.1,0.2

Answer 1

Допустим, что работа по перемещению малого поршня является затраченной, а работа по перемещению груза массой 2000 кг является полезной.
Aп/Аз×100%=n
(500 н×0,1 м/20000 н × s)×100%=n
50 Дж/0,8=20000 н × s
s=62,5 Дж/20000н
В данном случае приблизительное
значения расстояния будет равно 0,003 м

Answer 2

Calculation of the Displacement of the Large Piston

To calculate the displacement of the large piston, we can use the principle of work done. The work done by the small piston is equal to the work done on the large piston. The work done is given by the formula:

Work = Force x Distance

Given: - Force on the small piston (F1) = 500 H (H stands for hectonewton, which is equal to 100 newtons) - Distance moved by the small piston (d1) = 0.1 m - Mass lifted by the large piston (m2) = 2000 kg - Efficiency (η) = 0.8

We can calculate the force exerted by the large piston (F2) using the formula:

F2 = (F1 x d1) / (d2 x η)

Where: - F2 is the force exerted by the large piston - d2 is the displacement of the large piston

Rearranging the formula, we get:

d2 = (F1 x d1) / (F2 x η)

Substituting the given values, we can calculate the displacement of the large piston.

Let's calculate the displacement for each given option:

1. For the option 0.5: - d2 = (500 H x 0.1 m) / (0.5 x 0.8) = 125 m

2. For the option 1: - d2 = (500 H x 0.1 m) / (1 x 0.8) = 62.5 m

3. For the option 0.02: - d2 = (500 H x 0.1 m) / (0.02 x 0.8) = 3125 m

4. For the option 0.1: - d2 = (500 H x 0.1 m) / (0.1 x 0.8) = 625 m

5. For the option 0.2: - d2 = (500 H x 0.1 m) / (0.2 x 0.8) = 312.5 m

Therefore, the correct option is 0.1. The large piston will be displaced by 625 meters.