Question

К батарее с эдс 2в и внутренним сопротивлением 0.2 ом подключили резистор. определите сопротивление резистора и напряжение на нем если сила тока в цепи 0.4

Answer 1

I = эдс / (r+R)

r+R = эдс / I 

сопротивление резистора R = эдс / I  - r = 2в / 0.4А - 0.2 ом =4,8 Ом

напряжение U=I*R=0.4A*4.8Ом=1,92 В

Answer 2

Calculation of the Resistor's Resistance and Voltage

To determine the resistance of the resistor and the voltage across it, we need to use Ohm's Law, which states that the voltage across a resistor is equal to the current flowing through it multiplied by its resistance.

Given: - Battery voltage (V) = 2V - Internal resistance of the battery (r) = 0.2Ω - Current in the circuit (I) = 0.4A

We can calculate the resistance of the resistor (R) using the formula:

R = (V - Ir) / I

Substituting the given values:

R = (2V - (0.4A * 0.2Ω)) / 0.4A

Simplifying the equation:

R = (2V - 0.08V) / 0.4A

R = 1.92V / 0.4A

R = 4.8Ω

Therefore, the resistance of the resistor is 4.8Ω.

To calculate the voltage across the resistor, we can use Ohm's Law:

V = IR

Substituting the values:

V = (0.4A) * (4.8Ω)

V = 1.92V

Therefore, the voltage across the resistor is 1.92V.

Please note that the above calculations assume an ideal battery with no internal resistance. In reality, batteries have internal resistance, which affects the overall circuit behavior.