Question

В сосуд вместимостью 2 литра поместили азот массой 4 грамма и углекислый газ (СО2) массой 11 грамм при температуре 280 К. Определите давление смеси газов и ее молярную массу

Answer 1

 сосуд вместимостью v=2 литра поместили азот массой m1= 4 грамма и углекислый газ (СО2) массой m2=11 грамм при температуре T=280 К. Определите давление смеси газов и ее молярную массу
из уравнения Менделеева  - Клапейрона P*V=m*R*T/M
P1=m1*R*T/M1*V
P2=m2*R*T2/V*M2
по закону Дальтона  P= P1+P2=R*T*(m1/M1 +m2/M2)/V=
M = (m1 +m2)/ню= (m1  +m2)/(m1/M1+m2/M2)
M1=28*10^-3 кг/моль   M2=44*10^-3 кг/моль
вычисли сам у меня времени нет а решение 100% верное

Answer 2

Calculation of Pressure and Molar Mass of Gas Mixture

To determine the pressure and molar mass of the gas mixture in the vessel, we can use the ideal gas law equation:

PV = nRT

Where: - P is the pressure of the gas mixture - V is the volume of the vessel (2 liters) - n is the total number of moles of gas in the mixture - R is the ideal gas constant (8.314 J/(mol·K)) - T is the temperature of the gas mixture (280 K)

To find the number of moles of each gas, we need to use their respective molar masses. The molar mass of nitrogen (N2) is approximately 28 g/mol, and the molar mass of carbon dioxide (CO2) is approximately 44 g/mol.

Let's calculate the number of moles of each gas:

- Moles of nitrogen (N2): - Mass of nitrogen = 4 grams - Molar mass of nitrogen (N2) = 28 g/mol - Moles of nitrogen = Mass of nitrogen / Molar mass of nitrogen = 4 g / 28 g/mol = 0.143 moles

- Moles of carbon dioxide (CO2): - Mass of carbon dioxide = 11 grams - Molar mass of carbon dioxide (CO2) = 44 g/mol - Moles of carbon dioxide = Mass of carbon dioxide / Molar mass of carbon dioxide = 11 g / 44 g/mol = 0.25 moles

Now, let's calculate the total number of moles of gas in the mixture:

- Total moles of gas = Moles of nitrogen + Moles of carbon dioxide = 0.143 moles + 0.25 moles = 0.393 moles

Substituting the values into the ideal gas law equation, we can solve for the pressure (P):

P * 2 L = 0.393 mol * 8.314 J/(mol·K) * 280 K

Simplifying the equation:

P = (0.393 mol * 8.314 J/(mol·K) * 280 K) / 2 L

Calculating the pressure:

P ≈ 14.57 J/L

Therefore, the pressure of the gas mixture is approximately 14.57 J/L.

To calculate the molar mass of the gas mixture, we can use the formula:

Molar mass of gas mixture = (Mass of nitrogen + Mass of carbon dioxide) / Total moles of gas

Substituting the values:

Molar mass of gas mixture = (4 g + 11 g) / 0.393 mol

Calculating the molar mass of the gas mixture:

Molar mass of gas mixture ≈ 40.86 g/mol

Therefore, the molar mass of the gas mixture is approximately 40.86 g/mol.

Please note that the pressure and molar mass values provided are approximate, as the given molar masses of nitrogen and carbon dioxide are rounded values.