Question

Сможет ли деревянный брус массой 108 кг удержать над водой груз массой 70 кг? Плотность дерева равна 600 кг/м3 .

Answer 1

Выталкивающую силу, то есть силу архимеда найдем по формуле Fа=рgv.
V=m/p.  Vбруса=108\600=0.18 м^3.
Fа=600*0.18*10=1080 Н. - Выталкивающая сила. 
Ответ: да, брус массой 108 кг, сможет удержать груз массой 70 кг.

Answer 2

Can a wooden beam weighing 108 kg hold a load of 70 kg above water?

To determine if a wooden beam weighing 108 kg can hold a load of 70 kg above water, we need to consider the buoyancy force acting on the beam and the weight of the load.

The buoyancy force is the upward force exerted on an object submerged in a fluid, such as water. It is equal to the weight of the fluid displaced by the object. In this case, the wooden beam will displace a volume of water equal to its own volume.

To calculate the volume of the wooden beam, we need to know its dimensions. Unfortunately, the given information does not provide the dimensions of the beam. Therefore, we cannot accurately determine the volume of the beam and, consequently, the buoyancy force acting on it.

However, we can make a general observation. Wood has a density of approximately 600 kg/m³ Since the density of water is 1000 kg/m³, we can infer that the wooden beam will float in water. This means that the buoyancy force acting on the beam will be greater than its weight, allowing it to stay afloat.

Given this information, it is likely that the wooden beam weighing 108 kg will be able to hold a load of 70 kg above water. However, without specific dimensions and calculations, we cannot provide a definitive answer.

Please note that this response is based on general observations and assumptions. For a more accurate analysis, it is recommended to consult an engineer or a professional in the field of structural mechanics.

I hope this information helps! Let me know if you have any further questions.