Question

Дано: с= 4200 дж/кг*С , t1= 10C, t2= 60C, q1=2,7*10^7 ( ^ означает в степени 7) m2 = 40 кг , Q1=Q2/2 (/ деление) Найти m1 . Очень надо , заранее Спасибо ). Очень срочно нужно !

Answer 1

Q1=Q2/2
Q1=cm1(t2-t1)
Q2= qm2
cm1(t2-t1)=qm2/2
m2=((cm1(t2-t1))*2)/q
______________________________
m2=((4200 Дж(кг*с)*40кг(60-10 С))*2)/2,7*10^7 Дж/кг= 0,006 кг.
Ответ: m2= 0,006 кг.

Answer 2

Calculation of m1

To find the value of m1, we can use the equation Q1 = Q2/2, where Q1 is the heat absorbed by m1 and Q2 is the heat absorbed by m2.

The formula for heat transfer is given by Q = mcΔT, where Q is the heat transferred, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.

Given: - c = 4200 J/(kg·°C) - t1 = 10°C - t2 = 60°C - q1 = 2.7 * 10^7 J - m2 = 40 kg

First, let's calculate the heat absorbed by m2 (Q2) using the formula Q = mcΔT:

Q2 = m2 * c * (t2 - t1) Now, we can substitute the values into the equation:

Q2 = 40 kg * 4200 J/(kg·°C) * (60°C - 10°C)

Next, let's calculate Q1 using the equation Q1 = Q2/2:

Q1 = Q2/2

Finally, we can solve for m1 using the equation m1 = Q1 / (c * ΔT):

m1 = Q1 / (c * (t2 - t1)) Let's substitute the values and calculate m1.