Question

Цирковой акробат массой 80 кг бежит со скоростью 3,5 м/с навстречу лошади массой 246 кг, движущейся со скоростью 3,8 м/с и вскакивает на нее. Определите скорость лошади в тот момент, когда акробат скочил на нее.​

Answer 1

Ответ:

3.8-3.5=0.3км/год

Объяснение:

Answer 2

I can answer your question in detail. The circus acrobat of mass 80 kg runs at a speed of 3.5 m/s towards the horse of mass 246 kg, moving at a speed of 3.8 m/s, and jumps on it. To determine the speed of the horse at the moment when the acrobat jumped on it, we can use the conservation of momentum principle. This states that the total momentum of the system before the collision is equal to the total momentum of the system after the collision, assuming there are no external forces acting on the system.

The momentum of an object is equal to its mass multiplied by its velocity. Therefore, the momentum of the acrobat before the collision is 80 x 3.5 = 280 kg m/s, and the momentum of the horse before the collision is 246 x 3.8 = 934.8 kg m/s. The total momentum of the system before the collision is 280 + 934.8 = 1214.8 kg m/s.

After the collision, the acrobat and the horse move together with the same velocity, which we can call v. The mass of the system after the collision is 80 + 246 = 326 kg. The total momentum of the system after the collision is 326 x v. By the conservation of momentum principle, this must be equal to the total momentum before the collision. Therefore, we can write:

326 x v = 1214.8

Solving for v, we get:

v = 1214.8 / 326

v = 3.725 m/s

This is the speed of the horse at the moment when the acrobat jumped on it.

I hope this answer was helpful. If you want to learn more about the conservation of momentum principle, you can check out some of the web search results I found for you . Have a nice day!