Question

Мальчик вращает груз на веревочке длиной 50см. Чему равно центростремительное ускорение груза, если за 2 минуты он делает 60 оборотов ? помогите решить задачу ...

Answer 1

T=t/n=120/60=2 c  V=2*pi*R/T  a=V^2/R=4*pi^2*R/T^2=4*9,86*0,5/2^2=4,93 м/с2

Answer 2

Problem Analysis

We are given that a boy is rotating a weight on a string with a length of 50 cm. In 2 minutes, the weight completes 60 revolutions. We need to find the centripetal acceleration of the weight.

Solution

To find the centripetal acceleration, we can use the formula:

a = (4π²r) / T²

Where: - a is the centripetal acceleration - π is a mathematical constant approximately equal to 3.14159 - r is the radius of the circular path - T is the time taken for one revolution

In this case, the radius of the circular path is half the length of the string, which is 25 cm or 0.25 m. The time taken for one revolution is 2 minutes divided by 60, which is 2/60 or 1/30 minutes. We need to convert this to seconds, so it becomes 1/30 * 60 = 2 seconds.

Substituting the values into the formula, we get:

a = (4π² * 0.25) / (2²)

Simplifying further:

a = (4 * 3.14159² * 0.25) / 4

a = 3.14159² * 0.25

a ≈ 0.7854 m/s²

Therefore, the centripetal acceleration of the weight is approximately 0.7854 m/s².