Question

Заяженный шарик массой m=0,01 помещен в однородное направленное вертикально электрическое поле напряженностью Е=40 В/м За первую секунду с момиента начала движения он прошел вверх путь S=2 м Определить заряд q шарика. Считать ускорение свободного падения g=10м/с2

Answer 1

На тело действуют две силы..
Fк=qE- сила Кулона
Fт=mg-сила тяжести
Так как тело начало двигаться вверх, то сила Кулона больше, значит шарик имеет ускорение. Получается, что если он за секунду прошёл расстояние 2м, то ускорение за секунду а=2 м/с^2.
F=ma =>  F=Fк-Fт
Подставляем:
(Fк-Fт)=ma
qE-mg=ma
q=(ma+mg)/E
Остальное сами..

Answer 2

Problem Analysis

We are given the following information: - Mass of the charged ball: m = 0.01 kg - Electric field strength: E = 40 V/m - Distance traveled by the ball in the first second: S = 2 m - Acceleration due to gravity: g = 10 m/s^2

We need to determine the charge of the ball, q.

Solution

To solve this problem, we can use the equations of motion and the equation for the force experienced by a charged object in an electric field.

The equation of motion for an object moving in a uniform gravitational field is given by: S = ut + (1/2)gt^2 where: - S is the distance traveled - u is the initial velocity - g is the acceleration due to gravity - t is the time

In this case, the initial velocity, u, is 0 because the ball starts from rest.

The equation for the force experienced by a charged object in an electric field is given by: F = Eq where: - F is the force - E is the electric field strength - q is the charge of the object

Since the ball is moving vertically, the force experienced by the ball due to the electric field is in the opposite direction to the force due to gravity. Therefore, we can write: Eq = mg where: - m is the mass of the ball - g is the acceleration due to gravity

We can rearrange this equation to solve for the charge, q: q = mg/E

Now, let's substitute the given values into the equation to find the charge of the ball.

Calculation

Given: - m = 0.01 kg - E = 40 V/m - g = 10 m/s^2

Using the equation q = mg/E, we can calculate the charge of the ball: q = (0.01 kg * 10 m/s^2) / 40 V/m

Simplifying the equation: q = 0.001 C

Answer

The charge of the ball is 0.001 C.