Question

Пружина длиной 30 см под действием груза 4 кг удлинилась на 6 см. Вычислите работу растяжения пружины

Answer 1

30:6=5 4•5=20 5+20=25

Answer 2

Calculation of the Work Done by the Spring

To calculate the work done by the spring, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position. The formula for Hooke's Law is:

F = kx

Where: - F is the force exerted by the spring, - k is the spring constant, - x is the displacement of the spring.

In this case, we are given that the spring elongated by 6 cm (0.06 m) under the action of a 4 kg weight. We need to find the work done by the spring.

To calculate the spring constant (k), we can rearrange Hooke's Law formula as follows:

k = F / x

Substituting the given values, we have:

k = 4 kg * 9.8 m/s^2 / 0.06 m

Using the given values, we can calculate the spring constant (k) as follows:

k = 4 kg * 9.8 m/s^2 / 0.06 m = 653.33 N/m

Now that we have the spring constant, we can calculate the work done by the spring using the formula:

Work = (1/2) * k * x^2

Substituting the given values, we have:

Work = (1/2) * 653.33 N/m * (0.06 m)^2

Calculating the work done by the spring, we get:

Work = (1/2) * 653.33 N/m * 0.0036 m^2 = 0.589 Nm = 0.589 J

Therefore, the work done by the spring is 0.589 Joules.

Please note that the calculations provided above are based on the information given and the assumptions made.