Question

Скорость скатывающего с горы лыжника за 3 сек.увеличилась от 0,2 м/с до 2 м/с .Определите проекцию вектора ускорения лыжника на ось Х, сонаправленную со скоростью его движения

Answer 1

Дано:t=3cVo=0.2 м\сV=2 м\сa-?Решение:a=(V-Vo)\t=1.8\3=0.6м\с2Ответ: 0.6 м\с2

Answer 2

Calculation of the Acceleration Vector Projection on the X-axis

To determine the projection of the acceleration vector on the X-axis, we need to calculate the change in velocity and the time interval.

Given: - Initial velocity (v0) = 0.2 m/s - Final velocity (v) = 2 m/s - Time interval (t) = 3 seconds

The change in velocity (Δv) can be calculated by subtracting the initial velocity from the final velocity:

Δv = v - v0 = 2 m/s - 0.2 m/s = 1.8 m/s The acceleration (a) can be calculated using the formula:

a = Δv / t Substituting the values, we get:

a = 1.8 m/s / 3 s = 0.6 m/s²

The projection of the acceleration vector on the X-axis (ax) is equal to the acceleration (a) because the X-axis is parallel to the direction of motion (velocity) of the skier. Therefore:

ax = a = 0.6 m/s² So, the projection of the acceleration vector on the X-axis, which is parallel to the skier's velocity, is 0.6 m/s².