Question

Лыжник массой 60 кг,набравший за время спуска скорость 10 м/с, выехал на горизонтальный участок и остановился через 40 секунд. Определите силу трения на горизонтальном участке и коэффициенты трения скольжения.

Answer 1

вроде правильно, но я не знаю.

Answer 2

Problem Analysis

We are given the following information: - The mass of the skier is 60 kg. - The skier reaches a speed of 10 m/s during the descent. - The skier comes to a stop after 40 seconds on a horizontal section.

We need to determine the force of friction on the horizontal section and the coefficients of sliding friction.

Solution

To solve this problem, we can use the equations of motion. The force of friction can be calculated using the equation:

Force of friction = mass * acceleration

Since the skier comes to a stop, the acceleration on the horizontal section is equal to zero. Therefore, the force of friction is also equal to zero.

The coefficient of sliding friction can be calculated using the equation:

Coefficient of sliding friction = Force of friction / (mass * gravity)

Since the force of friction is zero, the coefficient of sliding friction is also zero.

Answer

The force of friction on the horizontal section is zero, and the coefficient of sliding friction is also zero.

Please let me know if I can help you with anything else.