Question

Человек прошел по прямой аллее парка 40 м до пересечения ее под углом 90 градусов с другой аллеи. Затем он повернул на вторую аллею и прошел по ней 30 м. Определите пройденный путь перемещения человека и покажите их на чертеже

Answer 1

L - путь, S - перемещение

$\bf L=L_1+L_2=40+30=70_M$
$\bf S= \sqrt{L_1^2+L_2^2} = \sqrt{40^2+30^2}=50_M$ (по теор. Пифагора)

Answer 2

Calculation of the Distance Traveled

To determine the distance traveled by the person, we can break down the movement into two parts: the distance traveled along the first alley and the distance traveled along the second alley.

1. Distance along the first alley: The person walked 40 meters along the first alley.

2. Distance along the second alley: After reaching the intersection, the person turned and walked along the second alley for 30 meters.

To calculate the total distance traveled, we can add the distances along the two alleys:

Total distance traveled = Distance along the first alley + Distance along the second alley = 40 meters + 30 meters = 70 meters.

Diagram

To illustrate the movement, we can provide a diagram:

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In the diagram, the vertical line represents the first alley, and the horizontal line represents the second alley. The person initially walks along the first alley for 40 meters and then turns to walk along the second alley for 30 meters.

Please note that the diagram is a simplified representation and may not be to scale.

I hope this helps! Let me know if you have any further questions.