Question

Снаряд массой 10 кг. В -верхний точке траектории имел скорость 300 м / с. В этой точке он разорвался надвое. меньше обломок массой 2 кг приобрел скорости 500 м / с и полетел вперед под углом 60 ° к плоскости горизонта. С какой скоростью и в каком направлении полетит больше обломок?

Answer 1

Ответ:

u2 = 331 м/с; β = 19,1°

Объяснение:

Answer 2

Calculation of the Velocity and Direction of the Larger Fragment

To determine the velocity and direction of the larger fragment, we can use the principle of conservation of momentum. According to this principle, the total momentum before the explosion is equal to the total momentum after the explosion.

Let's denote the velocity of the larger fragment as v and the angle it makes with the horizontal plane as θ.

The momentum before the explosion can be calculated as the sum of the momentum of the 10 kg projectile and the momentum of the smaller 2 kg fragment. Since the 10 kg projectile is at rest at the highest point of its trajectory, its momentum is zero. The momentum of the 2 kg fragment can be calculated as the product of its mass and velocity:

momentum_before = 2 kg × 500 m/s = 1000 kg·m/s.

The momentum after the explosion is the momentum of the larger fragment. We can break down the momentum into horizontal and vertical components:

momentum_after_horizontal = m × v × cos(θ),

momentum_after_vertical = m × v × sin(θ),

where m is the mass of the larger fragment.

Since the explosion occurs at the highest point of the trajectory, the vertical component of the momentum after the explosion is zero. Therefore, we have:

momentum_after_vertical = 0.

Using the principle of conservation of momentum, we can equate the momentum before the explosion to the momentum after the explosion:

momentum_before = momentum_after_horizontal.

Substituting the values, we get:

1000 kg·m/s = m × v × cos(θ).

To find the velocity v and the angle θ, we need additional information about the mass of the larger fragment. Unfortunately, the mass of the larger fragment is not provided in the question. Without this information, we cannot determine the velocity and direction of the larger fragment.

If you have any additional information or if you can provide the mass of the larger fragment, I would be happy to help you further.