Question

Поезд подходитк станции,тормозит с ускорением (-0,5 м/с²). Определите тормозной путь,если за 10 с до остановки скорость поезда была равно 36 км/ч

Answer 1

Тормозной путь s=v0*t-a*t²/2. Так как по условию v0=36 км/ч=36/3,6=10 м/с, то s=10*10-0,5*100/2=75 м. Ответ: 75 м.

Answer 2

Calculation of Braking Distance

To calculate the braking distance of the train, we need to use the equation:

d = (v^2 - u^2) / (2a)

where: - d is the braking distance - v is the final velocity (0 m/s, as the train comes to a stop) - u is the initial velocity (36 km/h, which needs to be converted to m/s) - a is the acceleration (-0.5 m/s²)

Let's calculate the braking distance step by step:

1. Convert the initial velocity from km/h to m/s: - 36 km/h = 36 * (1000 m / 3600 s) = 10 m/s

2. Plug the values into the equation: - d = (0^2 - 10^2) / (2 * -0.5) - d = (-100) / (-1) - d = 100 meters

Therefore, the braking distance of the train is 100 meters.