Question

Первый автомобиль проехал расстояние между двумя поселками за 3 часа без остановок, двигаясь прямолинейна и равномерно, а второй автомобиль ехал по тому же маршруту и с той же скоростью, но в середине пути сделал остановку на 1 час. Во сколько раз средняя скорость второго автомобиля меньше, чем первого?

Answer 1

Наверно 3 часа : 2 = 1,5 часа 

1,5 часа + 1 час = 2,5 часов 

2,5 + 1,5 часа (те которые мы разделили на 2 ) = 4 часа 

то-есть , скорость 2 авто на 1/4 меньше 1-ого авто

Answer 2

Calculation of Average Speed

To find the ratio of the average speeds of the two cars, we need to calculate the average speed for each car.

The first car traveled the distance between the two villages in 3 hours without any stops. Therefore, the average speed of the first car can be calculated by dividing the distance by the time taken:

Average speed of the first car = Distance / Time = x / 3 The second car also traveled the same distance with the same speed, but it made a 1-hour stop in the middle of the journey. This means that the second car was in motion for 2 hours, covering the same distance as the first car. Therefore, the average speed of the second car can be calculated as:

Average speed of the second car = Distance / Time = x / 2

Calculation of the Ratio

To find the ratio of the average speeds, we can divide the average speed of the second car by the average speed of the first car:

Ratio of average speeds = (x / 2) / (x / 3) = (3x) / (2x) = 3/2

Therefore, the average speed of the second car is 3/2 times (1.5 times) less than the average speed of the first car.

Please note that the actual value of the distance between the two villages, denoted by 'x' in the calculations, is not provided in the question. As a result, we cannot determine the exact numerical value of the ratio. However, we can conclude that the second car's average speed is 1.5 times less than the first car's average speed.

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