Question

Газ находится в закрытом баллоне при температуре 290К и давлении 810кПа. При какой температуре давление газа станет 1,12 МПа?

Answer 1

T1 = 290 K
p1 =810 кПа
р2 = 1,12 МПа = 1120 кПа
V = const
p1/p2 = T1/T2
T2 = T1 * p2/p1 = 290 * 1120/810 =400,9876  = 401 K
ответ
401 К

Answer 2

Calculation of the New Temperature

To determine the temperature at which the gas will have a pressure of 1.12 MPa, we can use the ideal gas law equation:

P1/T1 = P2/T2

Where: - P1 is the initial pressure of the gas (810 kPa) - T1 is the initial temperature of the gas (290 K) - P2 is the final pressure of the gas (1.12 MPa = 1120 kPa) - T2 is the final temperature of the gas (unknown)

We can rearrange the equation to solve for T2:

T2 = (P2 * T1) / P1

Substituting the given values:

T2 = (1120 kPa * 290 K) / 810 kPa

Calculating the result:

T2 ≈ 400 K

Therefore, the temperature at which the gas will have a pressure of 1.12 MPa is approximately 400 K.