Question

Шарик скатывается по желобу длинной 125 см с ускорением 1,6 м/с2. Какова скорость шарика в конце желоба? Начальная скорость шарика была равна нулю.

Answer 1

Решение на фото, успехов :)

Answer 2

Calculation of the Final Velocity of the Ball

To calculate the final velocity of the ball at the end of the chute, we can use the equations of motion. Given that the ball rolls down the chute with an acceleration of 1.6 m/s^2 and an initial velocity of 0 m/s, we can use the following equation:

v^2 = u^2 + 2as

Where: - v is the final velocity - u is the initial velocity - a is the acceleration - s is the distance traveled

In this case, the initial velocity (u) is 0 m/s, the acceleration (a) is 1.6 m/s^2, and the distance traveled (s) is 125 cm (or 1.25 m).

Plugging in these values into the equation, we get:

v^2 = 0^2 + 2 * 1.6 * 1.25

Simplifying the equation, we have:

v^2 = 0 + 4 * 1.25

v^2 = 5

Taking the square root of both sides, we find:

v = √5

Therefore, the final velocity of the ball at the end of the chute is approximately 2.24 m/s.