
При выполнении опыта на катоде выделилась медь массой 1,5 грамм за 20 мин при силе тока 4 ампир.
Определите по данным опыта электрохимический эквивалент меди.

Ответы на вопрос




Calculation of the Electrochemical Equivalent of Copper
To determine the electrochemical equivalent of copper based on the given experiment data, we need to use Faraday's laws of electrolysis. Faraday's first law states that the mass of a substance deposited or liberated during electrolysis is directly proportional to the quantity of electricity passed through it. The equation for Faraday's first law is:
m = (Q * M) / (n * F)
Where: - m is the mass of the substance deposited or liberated (in grams) - Q is the quantity of electricity passed through the substance (in coulombs) - M is the molar mass of the substance (in grams per mole) - n is the number of electrons involved in the reaction - F is Faraday's constant, which is approximately 96,485 coulombs per mole of electrons
In this case, we have the following information from the experiment: - Mass of copper deposited (m): 1.5 grams - Time of electrolysis (t): 20 minutes - Current (I): 4 amperes
To calculate the quantity of electricity passed (Q), we can use the equation:
Q = I * t
Substituting the given values, we have:
Q = 4 A * 20 min = 80 C
Now, we need to determine the molar mass of copper (M). The molar mass of copper is approximately 63.55 grams per mole.
Next, we need to determine the number of electrons involved in the reaction (n). In the case of copper, during electrolysis, each copper ion (Cu2+) gains two electrons to form copper metal. Therefore, the number of electrons involved in the reaction is 2.
Finally, we can calculate the electrochemical equivalent of copper (E) using the formula:
E = (m * n * F) / (Q * M)
Substituting the given values, we have:
E = (1.5 g * 2 * 96,485 C/mol) / (80 C * 63.55 g/mol)
Calculating this expression, we find that the electrochemical equivalent of copper is approximately 0.0372 grams per coulomb.
Please note that the above calculation assumes ideal conditions and does not take into account any potential losses or impurities in the experimental setup.


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