Question

Помогите пожалуйста срочно, прошу вас автомобиль двигаясь по прямолинейному участку шоссе со скоростью модуль которой 82 километров час обгоняет мотоциклиста. Чему равен модуль скорости движения мотоциклиста Если через промежуток времени 2,8 минут от момента обгона в расстояние между автомобилями мотоциклистом стало 1,4 км.

Answer 1

Скорость мотоциклиста будет равна 52 км/ч
Sа= U1/3.6*t   (t в СИ)
Sм= Sа - L    (L=1400м)
Uм= 3.6*(Sm/t)      (t d CИ)

Answer 2

I can help you with your question. According to Google Translate, your question is:

Answer in detail. Please help urgently, I beg you, a car moving along a straight section of the highway with a speed module of 82 km / h overtakes a motorcyclist. What is the modulus of the speed of the motorcyclist if after a period of 2.8 minutes from the moment of overtaking the distance between the cars and the motorcyclist became 1.4 km.

To solve this problem, we need to use the formula for relative speed and distance:

v = s / t

where v is the relative speed, s is the distance, and t is the time.

We know that the car and the motorcyclist are moving in the same direction, so the relative speed is the difference between their speeds:

v = v1 - v2

where v1 is the speed of the car and v2 is the speed of the motorcyclist.

We also know that the distance between them is 1.4 km and the time is 2.8 minutes, which is equal to 0.0467 hours. So we can plug these values into the formula:

v = s / t v = 1.4 / 0.0467 v = 30 km/h

This means that the car is moving 30 km/h faster than the motorcyclist. Since we know that the car's speed is 82 km/h, we can find the motorcyclist's speed by subtracting 30 km/h from it:

v2 = v1 - v v2 = 82 - 30 v2 = 52 km/h

Therefore, the modulus of the speed of the motorcyclist is 52 km/h. I hope this helps.