Question

Какое внутренне сопротивление имеет источник тока с ЭДС = 12 В, если при замыкании его параллельно соединенными резисторами R1=13 Ом и R2=8 Ом в цепи протекает ток I=2 А

Answer 1

$R= \frac{ R_{1} R_{2} }{ R_{1} + R_{2}} = \frac{13*8}{13+8}=4,95Om$

$U=IR=2*4,95=9,9B$

$U^{'}=E-U=12-9,9=2,1B$

$r= \frac{U^{'}}{I} = \frac{2,1}{2} =1,05 Om$

Answer 2

Calculation of Internal Resistance of the Current Source

To calculate the internal resistance of the current source, we can use Ohm's Law and the formula for calculating the total resistance in a parallel circuit.

Given: - EMF (Electromotive Force) of the current source (E) = 12 V - Current flowing through the circuit (I) = 2 A - Resistance of resistor R1 (R1) = 13 Ω - Resistance of resistor R2 (R2) = 8 Ω

We can start by calculating the total resistance in the circuit using the formula:

1/R_total = 1/R1 + 1/R2

Substituting the given values:

1/R_total = 1/13 + 1/8

Simplifying the equation:

1/R_total = (8 + 13)/(13 * 8) = 21/104

Taking the reciprocal of both sides:

R_total = 104/21 Ω

Now, we can calculate the internal resistance (r) of the current source using Ohm's Law:

E = I * (R_total + r)

Substituting the given values:

12 = 2 * (104/21 + r)

Simplifying the equation:

12 = (208/21) + 2r

Rearranging the equation:

2r = 12 - (208/21)

2r = (252 - 208)/21

2r = 44/21

r = 22/21 Ω

Therefore, the internal resistance of the current source is 22/21 Ω.

Please note that the above calculation is based on the given information and assumptions. If there are any additional factors or details that need to be considered, please provide them for a more accurate calculation.