Question

Колебательный контур состоит из конденсатора ёмкостью 1,2 мкФ и катушки индуктивностью 42 мГн. Определите период и частоту свободных электромагнитных колебаний в этом контуре.

Answer 1

По формуле Томсона: T= находишь период. а затем 1 делишь на период, это и есть частота.
Где С=1,2 мкФ =1,2*10^-6Ф
L= 42 мГн=42*10-3Гн

Answer 2

Calculation of Period and Frequency in an LC Circuit

To determine the period and frequency of free electromagnetic oscillations in the given circuit, we need to use the formula:

Period (T) = 2π√(LC)

where: - L is the inductance of the coil (42 mH or 0.042 H) - C is the capacitance of the capacitor (1.2 μF or 0.0000012 F)

Let's calculate the period and frequency using the given values:

Period (T) = 2π√(0.042 * 0.0000012) seconds

To find the frequency, we can use the formula:

Frequency (f) = 1 / T

Now, let's calculate the period and frequency:

Period (T) = 2π√(0.042 * 0.0000012) seconds

Frequency (f) = 1 / (2π√(0.042 * 0.0000012)) Hz

Calculating the values:

Period (T) ≈ 0.000366 seconds

Frequency (f) ≈ 2730 Hz

Therefore, the period of free electromagnetic oscillations in the given circuit is approximately 0.000366 seconds, and the frequency is approximately 2730 Hz.

Please note that the calculations were based on the given values of the inductance (42 mH) and capacitance (1.2 μF) of the circuit.