Question

Якорь судна вытесняет 200 л воды. Найти уменьшение его веса в море

Answer 1

Дано: V = 200 литров = 0,2 м³. Плотность морской воды р = 1025кг/м³.
ΔF - ?
По закону Архимеда, на тело, погруженное в жидкость (газ) действует выталкивающая сила, равная весу вытесненной жидкости (газа). В данном случае вытеснен объем морской воды V =200 литров.Вес этой воды равен F = V *p*g.  Таким образом на якорь действует выталкивающая сила F = 0,2*1025*10 = 2050 H. И именно на эту силу уменьшается вес якоря. Т.е. ΔF = 2050 H.

Answer 2

Finding the Weight Reduction of an Anchor in the Sea

To find the weight reduction of an anchor in the sea, we need to consider the principle of buoyancy. According to Archimedes' principle, an object submerged in a fluid experiences an upward buoyant force equal to the weight of the fluid it displaces. In this case, the anchor displaces 200 liters of water.

The weight reduction of the anchor in the sea can be calculated by finding the weight of the water displaced by the anchor. Since the density of water is approximately 1 gram per milliliter, we can convert the volume of water displaced to kilograms by multiplying it by the density of water.

Here's the calculation:

1. Convert the volume of water displaced from liters to milliliters: - 200 liters = 200,000 milliliters

2. Convert the volume of water displaced from milliliters to kilograms: - 200,000 milliliters * 1 gram/milliliter = 200,000 grams - 200,000 grams = 200 kilograms

Therefore, the weight reduction of the anchor in the sea is 200 kilograms.

Please note that the calculation assumes that the anchor is completely submerged in the water and that the density of the water remains constant.