Question

За вторую секунду после начала движения автомобиль проёшл 1.2 м. С каким ускорением он двигался?Определите перемещение автомобиля за десятую сукунду после начала движения.

Answer 1

S (1-2)= at2^2/2 - at1^2/2

1.2= 1.5a

a= 0.8 м/с^2

S (9-10) = at10^2/2 - at9^2/2 = 7,6 м

Answer 2

Calculation of Acceleration and Displacement

To determine the acceleration and displacement of the car, we can use the equations of motion. The equation for displacement is given by:

s = ut + (1/2)at^2

where: - s is the displacement - u is the initial velocity - a is the acceleration - t is the time

In this case, we are given that the car traveled a distance of 1.2 m in the second second of motion. This means that the displacement (s) after 2 seconds is 1.2 m. We can use this information to find the acceleration (a).

Let's calculate the acceleration first:

Given: - Initial velocity (u) = 0 m/s (since the car starts from rest) - Time (t) = 2 s - Displacement (s) = 1.2 m

Using the equation of motion, we can rearrange it to solve for acceleration (a):

a = (2s - 2ut) / t^2

Substituting the given values:

a = (2 * 1.2 - 2 * 0 * 2) / 2^2

Simplifying the equation:

a = 2.4 / 4

a = 0.6 m/s^2

Therefore, the car was moving with an acceleration of 0.6 m/s^2.

Now, let's determine the displacement of the car after 10 seconds:

Given: - Initial velocity (u) = 0 m/s (since the car starts from rest) - Time (t) = 10 s - Acceleration (a) = 0.6 m/s^2

Using the equation of motion, we can calculate the displacement (s):

s = ut + (1/2)at^2

Substituting the given values:

s = 0 * 10 + (1/2) * 0.6 * 10^2

Simplifying the equation:

s = 0 + (1/2) * 0.6 * 100

s = 0 + 0.3 * 100

s = 30 m

Therefore, the displacement of the car after 10 seconds is 30 meters.

Please note that these calculations assume constant acceleration throughout the motion of the car.