Question

1.Какое давление оказывает острие шилы, если сила давления равна 20Ньютон, а площадь острия 0,1мм в квадрате? С какой силой тело объемом 1 дм в кубе будет выталкиваться из ртути.Помогитеееееееееееее плиззззззз!!!!!!!!

Answer 1

1) p = $\frac{F}{S}$

F - сила ( 20 Н )
S - площадь ( 0,1 мм² = 0,0000001 м² )

p = $\frac{20}{0,0000001}$ = 200000000 Па = 0,2 ГПа

2) FA = p * g * V 

p - плотность жидкости ( 13600 кг / м³ )
g - ускорение свободного падения ( 10 Н / кг )
V - объём ( 10 дм³ = 0,001 м³ )

FA = 13600 * 10 * 0,001 = 136 H 

Answer 2

Pressure exerted by the tip of a needle

To calculate the pressure exerted by the tip of a needle, we can use the formula:

Pressure = Force / Area

Given that the force is 20 Newtons and the area of the tip is 0.1 mm², we need to convert the area to square meters before calculating the pressure.

Converting the area: 1 mm² = 0.000001 m²

So, the area of the tip in square meters is: 0.1 mm² * 0.000001 m²/mm² = 0.0000001 m²

Now, we can calculate the pressure: Pressure = 20 N / 0.0000001 m²

Calculating the pressure: Pressure = 200,000,000 N/m²

Therefore, the pressure exerted by the tip of the needle is 200,000,000 N/m² or 200,000,000 Pascal (Pa). [[1]]

Force required to displace an object in mercury

To calculate the force required to displace an object in mercury, we need to consider the buoyant force acting on the object.

The buoyant force is given by the formula:

Buoyant force = Density of fluid * Volume of fluid displaced * Acceleration due to gravity

In this case, the fluid is mercury, and the volume of the object is 1 dm³.

Converting the volume: 1 dm³ = 0.001 m³

Now, we can calculate the force: Buoyant force = Density of mercury * 0.001 m³ * Acceleration due to gravity

The density of mercury is approximately 13,600 kg/m³, and the acceleration due to gravity is approximately 9.8 m/s².

Calculating the force: Buoyant force = 13,600 kg/m³ * 0.001 m³ * 9.8 m/s²

Therefore, the force required to displace an object with a volume of 1 dm³ in mercury is approximately 133.28 Newtons (N). [[2]]

I hope this helps! Let me know if you have any further questions.