Question

Плачу 93 балла!: На больший поршень гидравлической машины положен груз массой 50 кг. Какую силу следует приложить к меньшему поршню,чтобы поднять груз, если площадь меньшего поршня 0,6см( см-в квадрате), а большего-24см(см-в квадрате).

Answer 1

По закону Паскаля
давление в гидравлической системе постоянно во всех точках
тогда  p =F1/S1 = F2/S2
F1/S1 = F2/S2
F1/S1 =m2g/S2
F1 = m2g *S1/S2 =50*10 * 0.6/24 =12,5 H
ОТВЕТ 12,5 Н

Answer 2

$\frac{F_1}{S_1}= \frac{F_2}{S_2}=const \\\ F_1= \frac{F_2S_1}{S_2} = \frac{m_2gS_1}{S_2} \\\ F_1= \frac{50kg\cdot 10m/s^2\cdot0.6\cdot10^{-4}m^2}{24\cdot10^{-4}m^2} =12.5H$
Ответ: 12,5 Н

Answer 3

Calculation of the Force Required to Lift the Load

To calculate the force required to lift the load using a hydraulic machine, we can apply Pascal's law, which states that the pressure exerted on a fluid is transmitted equally in all directions. In this case, the pressure exerted on the larger piston is transmitted to the smaller piston, allowing it to lift the load.

The formula to calculate the force is:

Force on the larger piston / Force on the smaller piston = Area of the smaller piston / Area of the larger piston

Given the following values: - Mass of the load (m) = 50 kg - Area of the smaller piston (A1) = 0.6 cm^2 - Area of the larger piston (A2) = 24 cm^2

We can rearrange the formula to solve for the force on the smaller piston:

Force on the smaller piston = (Force on the larger piston * Area of the smaller piston) / Area of the larger piston

Let's substitute the values into the formula and calculate the force on the smaller piston.

Force on the smaller piston = (50 kg * 9.8 m/s^2 * 0.6 cm^2) / 24 cm^2

Note: We need to convert the area from cm^2 to m^2 to maintain consistent units.

Converting cm^2 to m^2: 1 cm^2 = 0.0001 m^2

Force on the smaller piston = (50 kg * 9.8 m/s^2 * 0.6 * 0.0001 m^2) / (24 * 0.0001 m^2)

Simplifying the equation:

Force on the smaller piston = (50 * 9.8 * 0.6) / 24

Now, let's calculate the force on the smaller piston.

Force on the smaller piston = (50 * 9.8 * 0.6) / 24 = 7.75 N

Therefore, to lift the load, a force of 7.75 N should be applied to the smaller piston.