Question

Тело массой 100 кг поднимают с помощью троса с каким ускорением движется тело если трос жесткостью 59 кH/M удлинился на 20мм

Answer 1

Спроси у твоей мамы и всё или у родных

Answer 2

Calculation of Acceleration

To calculate the acceleration of the body, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma).

In this case, the force acting on the body is the tension in the rope. The change in length of the rope can be used to calculate the change in tension.

Given: - Mass of the body (m) = 100 kg - Stiffness of the rope (k) = 59 kN/m - Change in length of the rope (ΔL) = 20 mm = 0.02 m

To calculate the change in tension (ΔT), we can use Hooke's law, which states that the force exerted by a spring is directly proportional to the change in length of the spring.

ΔT = k * ΔL

Now, we can calculate the acceleration (a) using Newton's second law:

a = ΔT / m

Let's plug in the values and calculate the acceleration.

Calculation:

Given: - Mass of the body (m) = 100 kg - Stiffness of the rope (k) = 59 kN/m - Change in length of the rope (ΔL) = 0.02 m

Using Hooke's law, we can calculate the change in tension (ΔT):

ΔT = k * ΔL = 59 kN/m * 0.02 m = 1.18 kN

Now, we can calculate the acceleration (a) using Newton's second law:

a = ΔT / m = 1.18 kN / 100 kg = 11.8 m/s²

Therefore, the body is moving with an acceleration of 11.8 m/s².

Conclusion:

The body with a mass of 100 kg is moving with an acceleration of 11.8 m/s² when the rope with a stiffness of 59 kN/m elongates by 20 mm.