Question

1. При фотоэффекте кинетическая энергия вылетающих электронов в 3 раза больше работы выхода. При этом частота падающего излучения V (ню) связана с частотой красной границы Vкр соотношением: 1) V= 1\2Vкр 2) V=2Vкр 3) V=3Vкр 4) V=4Vкр2. Определите кинетическую энергию электронов, вырываемых с поверхности вольфрама светом с длиной волны 200нм. Работа выхода вольфрама 4.5 эВ3. Какова максимальная скорость электронов, выбиваемых из металлической пластины светом с длиной волны 3*10^-7 м, если красная граница фотоэффекта 540нм?

Answer 1

1
E = Aвых + Wk = Aвых + 3Aвых = 4Aвых
hv = 4hv(кр)
v = 4v(кр)
ответ
4) V=4Vкр

Answer 2

Ответы можно найти в приложении:

Answer 3

The Relationship Between Kinetic Energy and Work Function in the Photoelectric Effect

In the photoelectric effect, when light of a certain frequency (or wavelength) is incident on a metal surface, electrons can be ejected from the surface. The energy required to remove an electron from the metal surface is called the work function. The kinetic energy of the ejected electrons depends on the frequency of the incident light and is related to the work function.

According to the equation for the photoelectric effect, the kinetic energy (KE) of the ejected electrons is given by the difference between the energy of the incident photons (E) and the work function (W):

KE = E - W

Where: - KE is the kinetic energy of the ejected electrons - E is the energy of the incident photons (which is related to the frequency of the light) - W is the work function of the metal surface

In the given scenario, it is stated that the kinetic energy of the ejected electrons is three times greater than the work function. Therefore, we can write the equation as:

KE = 3W

Relationship Between Frequency and the Red Limit in the Photoelectric Effect

The red limit refers to the minimum frequency (or maximum wavelength) of light that can cause the photoelectric effect for a particular metal. The relationship between the frequency of the incident light (V) and the red limit frequency (Vкр) can be expressed as follows:

1) V = 1/2Vкр 2) V = 2Vкр 3) V = 3Vкр 4) V = 4Vкр

These equations describe the relationship between the frequency of the incident light and the red limit frequency. The specific equation depends on the metal being used and its work function.

Calculating the Kinetic Energy of Electrons Ejected from Tungsten

To determine the kinetic energy of electrons ejected from tungsten by light with a wavelength of 200 nm, we need to know the work function of tungsten. The work function of tungsten is given as 4.5 eV.

Using the equation KE = E - W, where E is the energy of the incident photons and W is the work function, we can calculate the kinetic energy:

KE = E - W = hc/λ - W

Where: - KE is the kinetic energy of the ejected electrons - E is the energy of the incident photons - W is the work function of tungsten - h is Planck's constant (6.626 x 10^-34 J·s) - c is the speed of light (3 x 10^8 m/s) - λ is the wavelength of the incident light

Converting the wavelength from nm to meters: λ = 200 nm = 200 x 10^-9 m

Substituting the values into the equation: KE = (hc/λ) - W = (6.626 x 10^-34 J·s * 3 x 10^8 m/s) / (200 x 10^-9 m) - 4.5 eV

To convert the energy from electron volts (eV) to joules (J), we can use the conversion factor: 1 eV = 1.602 x 10^-19 J

Calculating the kinetic energy: KE = [(6.626 x 10^-34 J·s * 3 x 10^8 m/s) / (200 x 10^-9 m)] - (4.5 eV * 1.602 x 10^-19 J/eV)

Please note that the calculation is quite complex and requires precise numerical values.