Question

Сопротивление двух ламп, включённых параллельно в сеть с напряжением120 В, относится, как 3 : 2. Определить потребляемые лампами мощности и их сопротивления в режиме горения, если сила тока в первой лампе составляет 0,4 А.

Answer 1

R1 (в рабочем режиме) = U/I1 = 220/0.4 = 550 Ом
R2 = 2R1/3 = 367 Ом
W1 = U²/R1 = 220²/550 = 88 Вт
W2 = U²/R2 = 220²/367 = 132 Вт

Answer 2

Calculation of Power and Resistance in Parallel Circuit

To determine the power consumed by the lamps and their resistances in the burning mode, we need to consider the given information. Two lamps are connected in parallel to a power supply with a voltage of 120 V. The ratio of the resistance of the two lamps is given as 3:2, and the current flowing through the first lamp is 0.4 A.

First, let's calculate the resistance of the first lamp. We know that the current flowing through the first lamp is 0