Question

Решите, Когда тело массой 10 кг опустили в воду оно потеряла в весе 25 ньютонов Какая действовала на него архемедова сила? Каков стал вес этого тела в воде?

Answer 1

Р(в воде)=P(в воздухе)-F арх=mg-Fарх=10*10-25=75 [Н]
Fарх-25 Н

Answer 2

Archimedes' Principle and Weight Loss in Water

When an object is submerged in a fluid, it experiences an upward buoyant force known as Archimedes' force. This force is equal to the weight of the fluid displaced by the object. According to Archimedes' principle, the buoyant force acting on an object is equal to the weight of the fluid displaced by the object.

In this case, a body with a mass of 10 kg lost 25 Newtons of weight when submerged in water. We can use Archimedes' principle to determine the buoyant force acting on the body and the weight of the body in water.

The buoyant force (Fb) acting on the body is equal to the weight of the fluid displaced by the body. Since the body is submerged in water, the buoyant force is equal to the weight of the water displaced by the body.

To calculate the weight of the water displaced, we can use the equation:

Weight of water displaced = density of water × volume of water displaced

The density of water is approximately 1000 kg/m^3. To find the volume of water displaced, we can use the fact that the weight loss of the body in water is equal to the buoyant force acting on it.

Therefore, the weight loss of 25 Newtons is equal to the buoyant force acting on the body, which is equal to the weight of the water displaced.

Now, let's calculate the weight of the water displaced and the weight of the body in water.

Calculation:

1. Calculate the weight of the water displaced: - Weight of water displaced = density of water × volume of water displaced - Density of water = 1000 kg/m^3 - Weight loss of the body = 25 N

Using the equation, we can rearrange it to solve for the volume of water displaced:

Volume of water displaced = Weight loss of the body / Density of water

Substituting the given values:

Volume of water displaced = 25 N / 1000 kg/m^3

Volume of water displaced = 0.025 m^3

Therefore, the volume of water displaced by the body is 0.025 cubic meters.

2. Calculate the weight of the body in water: - Weight of the body in water = Weight of the body - Weight of water displaced

The weight of the body is given as 10 kg. To convert it to Newtons, we can use the equation:

Weight (in Newtons) = mass × acceleration due to gravity

The acceleration due to gravity is approximately 9.8 m/s^2.

Weight of the body = 10 kg × 9.8 m/s^2

Weight of the body = 98 N

Substituting the values:

Weight of the body in water = 98 N - 25 N

Weight of the body in water = 73 N

Therefore, the Archimedes' force acting on the body is 25 Newtons, and the weight of the body in water is 73 Newtons.

Please note that the calculations provided are based on the information given and the assumption that the body is fully submerged in water.