Question

Снаряд вылетает из орудия под углом 45гр к горизонту. Чему равна дальность полета снаряда, если радиус кривизны траектории в точке максимального подъема равен 15 км?

Answer 1

Радиус кривизна траектории в точке максимального подъема равен максимальной высоте подъема
H=V0^2*sin^2a/2g
V0^2=H*2g/sin^a
L=sin2a*V0^2/g
L-дальность полета
L=V0^2/g=H*2/sin^2a=15*4=60км

Answer 2

Calculation of Projectile Range

To calculate the range of a projectile launched at an angle of 45 degrees to the horizon, we can use the following formula:

Range = (2 * velocity^2 * sin(angle) * cos(angle)) / g

Where: - velocity is the initial velocity of the projectile - angle is the launch angle - g is the acceleration due to gravity (approximately 9.8 m/s^2)

In this case, we are given that the radius of curvature of the trajectory at the point of maximum elevation is 15 km. However, this information alone is not sufficient to calculate the range of the projectile. We need the initial velocity of the projectile to proceed with the calculation.

Please provide the initial velocity of the projectile so that we can calculate the range accurately.