Question

Находившийся в закрытом баллоне нагрели от 300 до 360 К, при этом давление возросло на 81 КПа. Определить первоначальное давление.

Answer 1

объем у них одинаковый 

изохорный процесс

Х первон давление  300/х=360/х+81 

60х=300*81

х=405кпа 

 

Answer 2

Calculation of Initial Pressure in a Closed Container

To determine the initial pressure in a closed container that was heated from 300 K to 360 K, resulting in a pressure increase of 81 kPa, we can use the ideal gas law. The ideal gas law states that the pressure (P), volume (V), and temperature (T) of a gas are related by the equation:

PV = nRT

Where: - P is the pressure of the gas - V is the volume of the gas - n is the number of moles of the gas - R is the ideal gas constant (8.314 J/(mol·K)) - T is the temperature of the gas in Kelvin

In this case, we are assuming that the volume and the number of moles of the gas remain constant. Therefore, we can rewrite the equation as:

P1/T1 = P2/T2

Where: - P1 is the initial pressure - T1 is the initial temperature - P2 is the final pressure - T2 is the final temperature

We can rearrange the equation to solve for the initial pressure (P1):

P1 = (P2 * T1) / T2

Given that the final temperature (T2) is 360 K, the final pressure (P2) is the initial pressure (P1) plus the pressure increase of 81 kPa, and the initial temperature (T1) is 300 K, we can substitute these values into the equation to calculate the initial pressure.

P1 = ((P1 + 81) * 300) / 360

To solve this equation, we can simplify it as follows:

360 * P1 = (P1 + 81) * 300

360P1 = 300P1 + 24300

60P1 = 24300

P1 = 24300 / 60

P1 = 405 kPa

Therefore, the initial pressure in the closed container was 405 kPa.