Question

Снаряд летит с горизонтальной скоростью 600 м/с и разрывается на два осколка. Один из осколков большей массы падает по вертикали, а другой, массы в два раза меньшей первого, движется после разрыва под углом 30° к горизонту. Найдите скорости осколков непосредственно после разрыва.

Answer 1

Ответ. m*v0=(m*u1)/3; (m*u2)/3+(2*m*u3)/3=0; u1=3*v0; u2=u1*tg(a); u3=0,5*u2; u1=1800; u2=1800/(3^0,5);
u3=600/(3^0,5); u=(u1^2+u2^2)^0,5; u=1800*(4/3)^0,5; u=3600/(3^0,5);

Answer 2

Problem Analysis

We are given that a projectile is moving horizontally with a speed of 600 m/s and it breaks into two fragments. One fragment, which has a greater mass, falls vertically, while the other fragment, which has a mass half that of the first fragment, moves at an angle of 30° to the horizontal. We need to find the velocities of the fragments immediately after the break.

Solution

Let's assume the mass of the first fragment is m and the mass of the second fragment is m/2.

We know that the total momentum before the break is equal to the total momentum after the break. Since there is no external force acting on the system, the total momentum is conserved.

The total momentum before the break is given by the product of the mass and velocity of the projectile, which is m × 600 m/s.

After the break, the first fragment falls vertically, so its horizontal velocity is zero. The second fragment moves at an angle of 30° to the horizontal. Let's assume its horizontal velocity is v.

Using the conservation of momentum, we can write the equation:

m × 600 m/s = m × 0 m/s + (m/2) × v

Simplifying the equation, we get:

600 = v/2

Solving for v, we find:

v = 1200 m/s

Therefore, the velocity of the first fragment immediately after the break is 0 m/s and the velocity of the second fragment is 1200 m/s at an angle of 30° to the horizontal.

Answer

The velocity of the first fragment immediately after the break is 0 m/s and the velocity of the second fragment is 1200 m/s at an angle of 30° to the horizontal.