Question

Помогите мне пожалуйста электродвигатель потребляет ток 20 А при напряжении 220в определите полную работу тока двигателя и количество теплоты выделившейся за 30 мин если сопротивление обмотки двигателя 0,75 Ом

Answer 1

Полная работа тока $A=UIt=220*20*1800=792000$Дж=7,92 МДж

Количество теплоты в обмотке $Q=I^{2}Rt=20^{2}*0,75*1800=540000$Дж=540 кДж

Answer 2

Calculation of Total Work and Heat Produced by the Motor

To determine the total work done by the motor and the amount of heat produced, we can use the formulas:

1. Total work (W) = Current (I) * Voltage (V) * Time (t) 2. Heat produced (Q) = Current (I)^2 * Resistance (R) * Time (t)

Given: - Current (I) = 20 A - Voltage (V) = 220 V - Time (t) = 30 min = 30 * 60 s = 1800 s - Resistance (R) = 0.75 Ω

Using the above formulas, we can calculate the total work and heat produced by the motor.

1. Total work (W) = 20 A * 220 V * 1800 s = 792,000 J

The total work done by the motor is 792,000 Joules.

2. Heat produced (Q) = (20 A)^2 * 0.75 Ω * 1800 s = 540,000 J

The amount of heat produced by the motor is 540,000 Joules.

Please note that the above calculations assume that the motor operates at a constant current and voltage throughout the given time period.