Question

Какое количество теплоты потребуется для плавления стального цилиндра массой 4 кг взятого при температуре плавления

Answer 1

Дано:
$m=4kg$
λ $=84000 \frac{Dg}{kg}$
$-----$
$Q-?$

Решение:
$Q=$ λ $m$
$Q=84000 \frac{Dg}{kg}*4kg= 336000Dg=336kDg$

Ответ: $Q=336kDg$

Answer 2

Calculating the Heat Required to Melt a Steel Cylinder

To calculate the heat required to melt a steel cylinder, we can use the formula:

Q = m * L

Where: - Q = heat required - m = mass of the steel cylinder - L = latent heat of fusion for steel

Given: - Mass of the steel cylinder, m = 4 kg - Latent heat of fusion for steel, L = 120 J/g

Calculation

Converting the mass from kg to g: - 1 kg = 1000 g - Therefore, 4 kg = 4000 g

Using the formula, we can calculate the heat required:

Q = 4000 g * 120 J/g

Q = 480,000 J

So, the heat required to melt the steel cylinder with a mass of 4 kg at its melting temperature is 480,000 Joules.

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