Question

Сколько теплоты выделится при конденсации 3 кг аммиака,взятого при температуре кипения?

Answer 1

900000 - удельная теплота парообразования спирта 
2500 - удельная теплоемкость спирта 
60 - изменение температуры

 

  0,2*900000=180000 
0,2*2500*60=30000 
-180000+(-30000)=-210000 Дж или 210 кДж 

Answer 2

Calculating Heat Released During Ammonia Condensation

To calculate the heat released during the condensation of 3 kg of ammonia at its boiling temperature, we can use the formula:

q = mL

Where: - q is the heat released - m is the mass of the substance - L is the latent heat of condensation

Given: - m = 3 kg - L = 2300000 J/kg

Using the formula, we can calculate the heat released:

q = 3 kg * 2300000 J/kg = 6900000 J

So, 6900000 joules of heat will be released during the condensation of 3 kg of ammonia at its boiling temperature