Question

При температуре 300 К давление идеального газа в закрытом сосуде равно 75кПа.Чему будет равно давление газа при его нагревании до 320 К?.Процесс считать изохорным.

Answer 1

При изохорном процессе соблюдается равенство
р1/t1=p2/t2 , откуда   р2=p1·T2/T1            p2=75000·320/300=80000Па=80кПа

Answer 2

Calculation of Pressure Change in an Isochoric Process

To calculate the change in pressure of an ideal gas during an isochoric (constant volume) process, we can use the ideal gas law equation:

PV = nRT

Where: - P is the pressure of the gas - V is the volume of the gas (which remains constant in an isochoric process) - n is the number of moles of the gas - R is the ideal gas constant - T is the temperature of the gas in Kelvin

In this case, we are given that the initial temperature (T1) is 300 K and the initial pressure (P1) is 75 kPa. We need to find the final pressure (P2) when the temperature increases to 320 K.

Since the process is isochoric, the volume remains constant. Therefore, we can rewrite the ideal gas law equation as:

P1/T1 = P2/T2

Where: - P1 is the initial pressure - T1 is the initial temperature - P2 is the final pressure (which we need to find) - T2 is the final temperature

Now, we can substitute the given values into the equation and solve for P2:

P1/T1 = P2/T2

75 kPa / 300 K = P2 / 320 K

To solve for P2, we can cross-multiply and then divide:

P2 = (75 kPa / 300 K) * 320 K

Calculating this expression, we find that the final pressure (P2) when the temperature increases to 320 K is approximately 80 kPa.

Please note that the above calculation assumes that the gas behaves ideally and that there are no other factors affecting the gas behavior.