Question

Работа выхода электрона из ртути равна 4.53 эВ. При какой частоте излучения запирающее напряжение окажется равным 3В

Answer 1

по формуле Эйнштейна
h*v=A+е*U
v=(4,53+4)*1,6*10^-19/6,63*10^-34=2*10^15 Гц

Answer 2

Calculating the Frequency of Radiation for Mercury Electron Emission

The work function for the emission of an electron from mercury is given as 4.53 eV. We need to find the frequency of the radiation when the stopping voltage is 3V.

To calculate the frequency of the radiation, we can use the equation:

E = hf - φ

Where: - E is the energy of the incident photon - h is Planck's constant (6.626 x 10^-34 J·s) - f is the frequency of the incident photon - φ is the work function

First, we need to convert the work function from electron volts (eV) to joules (J): 1 eV = 1.602 x 10^-19 J

So, the work function in joules is: φ = 4.53 eV * 1.602 x 10^-19 J/eV

Now, we can rearrange the equation to solve for the frequency: f = (E + φ) / h

Substitute the given values: f = (3V * 1.602 x 10^-19 J/eV + 4.53 eV * 1.602 x 10^-19 J/eV) / 6.626 x 10^-34 J·s

Calculating the frequency using the given values: f ≈ 6.32 x 10^14 Hz

So, the frequency of the radiation when the stopping voltage is 3V is approximately 6.32 x 10^14 Hz.