Question

Конденсатор емкостью 1 мкФ при напряжении 1200 В применяют для импульсной стыковой сварки медной проволоки. Найти среднюю полезную мощность разряда, если он длится 1 мкс. КПД установки 4 %.

Answer 1

P=0,04*E/t=0,04*C*U^2/2*t=0,04*10^-6*144*10^4/2*10^-6=5,76*10^4 Вт

Answer 2

Calculation of Average Useful Power

To find the average useful power of the discharge, we can use the formula:

Average Power (P) = Energy (E) / Time (t)

The energy stored in a capacitor can be calculated using the formula:

Energy (E) = 0.5 * C * V^2

Where: - C is the capacitance of the capacitor (1 μF) - V is the voltage across the capacitor (1200 V)

Given that the discharge time (t) is 1 μs, we can substitute these values into the formulas to find the average useful power.

Step 1: Calculate the energy stored in the capacitor.

E = 0.5 * C * V^2

E = 0.5 * 1 μF * (1200 V)^2

E = 0.5 * 1 * 1e-6 F * (1200)^2 V^2

E = 0.5 * 1 * 1e-6 * 1440000 J

E = 0.72 J

Step 2: Calculate the average useful power.

P = E / t

P = 0.72 J / 1 μs

P = 0.72 J / 1e-6 s

P = 0.72 * 10^6 W

P = 720,000 W

Therefore, the average useful power of the discharge is 720,000 watts.

Efficiency of the Setup

The efficiency (η) of the setup is given as 4%. Efficiency is defined as the ratio of useful output power to the input power.

Efficiency (η) = (Useful Power / Input Power) * 100

Given that the efficiency is 4%, we can calculate the input power.

Step 1: Calculate the input power.

Input Power = Useful Power / (Efficiency / 100)

Input Power = 720,000 W / (4 / 100)

Input Power = 720,000 W / 0.04

Input Power = 18,000,000 W

Therefore, the input power of the setup is 18,000,000 watts.

Please note that the efficiency of the setup is provided as 4%, but the specific details of the setup are not mentioned in the question.