Question

Тело поднятое на высоту 1 м падает на землю без начальной скорости. масса тела равна 4,6 кг. найти кинетическую энергию в момент его падения. ускорение свободного падения равно 9,8 м\с2

Answer 1

220 Джоулей как бы, кто придумал что мне надо писать 20 символов тому лично руку пожму, сока 

Answer 2

Problem Statement

We are given the following information: - The body is lifted to a height of 1 m. - The body falls to the ground without any initial velocity. - The mass of the body is 4.6 kg. - The acceleration due to gravity is 9.8 m/s^2.

We need to find the kinetic energy of the body at the moment it hits the ground.

Solution

To find the kinetic energy of the body at the moment it hits the ground, we can use the formula:

Kinetic Energy (KE) = 1/2 * mass * velocity^2

Since the body falls freely without any initial velocity, its velocity just before hitting the ground can be calculated using the equation:

v = sqrt(2 * g * h)

where: - v is the velocity of the body just before hitting the ground, - g is the acceleration due to gravity (9.8 m/s^2), - h is the height from which the body is dropped (1 m).

Let's calculate the velocity first:

v = sqrt(2 * 9.8 * 1) = sqrt(19.6) ≈ 4.427 m/s

Now, we can calculate the kinetic energy using the formula:

KE = 1/2 * mass * velocity^2

KE = 1/2 * 4.6 * (4.427)^2 ≈ 45.94 J

Therefore, the kinetic energy of the body at the moment it hits the ground is approximately 45.94 J.