Question

При подключении лампочки накаливания к источнику тока с ЭДС 10В,напряжение равно 8 В.Определите КПД источника тока

Answer 1

Кпд=U*100%/E=8*100%/10=80%

Answer 2

Calculation of Efficiency (КПД) of the Power Source

To calculate the efficiency (КПД) of the power source when connecting an incandescent light bulb, we need to know the voltage and the electromotive force (ЭДС) of the power source.

Given: - Voltage (напряжение) = 8 V - Electromotive force (ЭДС) = 10 V

The efficiency (КПД) of a power source is defined as the ratio of the useful power output to the total power input. In this case, the useful power output is the power consumed by the incandescent light bulb.

To calculate the efficiency, we need to determine the power consumed by the incandescent light bulb. The power (P) can be calculated using the formula:

P = V * I

Where: - P is the power consumed by the incandescent light bulb - V is the voltage across the incandescent light bulb - I is the current flowing through the incandescent light bulb

To find the current (I), we can use Ohm's Law:

I = V / R

Where: - R is the resistance of the incandescent light bulb

The resistance of an incandescent light bulb can vary, but for this calculation, we'll assume a resistance of 10 ohms.

Substituting the values into the formulas, we can calculate the power consumed by the incandescent light bulb:

I = V / R = 8 V / 10 Ω = 0.8 A

P = V * I = 8 V * 0.8 A = 6.4 W

Now that we have the power consumed by the incandescent light bulb, we can calculate the efficiency (КПД) of the power source using the formula:

Efficiency (КПД) = (Power output / Power input) * 100%

In this case, the power input is the electromotive force (ЭДС) of the power source, which is 10 V.

Efficiency (КПД) = (6.4 W / 10 W) * 100% = 64%

Therefore, the efficiency (КПД) of the power source when connecting the incandescent light bulb is 64%.

Please note that the resistance of the incandescent light bulb and the efficiency calculation may vary depending on the specific characteristics of the bulb and the power source.