Question

На сколько уменьшится длина пружины, если ее сжимать силой 20Н?Жесткость пружины равна 400Н/М

Answer 1

F=20H
x=400H/м
k-?
F=k*x(формула упругости)->k=F/x=20 H/400 H/м=0.05 м(длина пружины)=5 см
Ответ:5 см.

Answer 2

Calculation of the Change in Length of a Spring

To calculate the change in length of a spring when compressed with a force of 20 N, we need to use Hooke's Law, which states that the force exerted on a spring is directly proportional to the displacement of the spring from its equilibrium position.

The formula for Hooke's Law is:

F = k * Δl

Where: - F is the force applied to the spring (20 N in this case) - k is the spring constant or stiffness of the spring (400 N/m in this case) - Δl is the change in length of the spring

To find Δl, we rearrange the formula:

Δl = F / k

Substituting the given values:

Δl = 20 N / 400 N/m

Calculating the result:

Δl = 0.05 m

Therefore, the length of the spring will decrease by 0.05 meters when compressed with a force of 20 N.