Question

Автомобиль массой 14 тонн трогаясь с места, проходит первые 50 метров за 10 сек. Найти силу тяги, если коэффициент сопротивления равен 0,05.

Answer 1

По второму Закону Ньютона

m*a=F-m*g*м

a=2S/t^2

F=m*((2S/t^2)+g*м)/а

м-коэффициент сопротивления равен 0,05

S=50 м

t= 10 с

Answer 2

Calculation of Tractive Force

To find the tractive force of a vehicle, we can use the equation:

Tractive Force = Mass * Acceleration

In this case, the mass of the vehicle is given as 14 tons, which is equivalent to 14,000 kilograms. The acceleration can be calculated using the formula:

Acceleration = Distance / Time^2

The distance covered by the vehicle is 50 meters, and the time taken is 10 seconds. Plugging these values into the equation, we can find the acceleration.

Let's calculate the tractive force step by step:

1. Convert the mass of the vehicle from tons to kilograms: - 1 ton = 1,000 kilograms - Therefore, 14 tons = 14,000 kilograms

2. Calculate the acceleration: - Distance = 50 meters - Time = 10 seconds - Acceleration = 50 / (10^2) = 50 / 100 = 0.5 meters per second squared

3. Calculate the tractive force: - Tractive Force = Mass * Acceleration - Tractive Force = 14,000 kg * 0.5 m/s^2 = 7,000 Newtons

Therefore, the tractive force of the vehicle is 7,000 Newtons.