Question

В железную кастрюлю массой 1,5 кг налили 2,5 кг воды, температура которой равна 20 Градусов Цельсия. Какой количество теплоты необходимо передать кастрюле, чтобы вода в ней закипела?

Answer 1

) Q = cmΔt 

c - удельная теплоёмкость ( для железа 444 Дж / кг * С ; для воды 4200 Дж / кг * С --------> 444 + 4200 = 4644 Дж / кг * С ) 
m - масса ( 1,5 кг + 2,5 кг = 4 кг ) 
Δt - разности температур ( 100 С ( температура кипения ) - 20 С = 80 С ) 

Q = 4644 * 4 * 80 = 1486080 Дж = 1486,08 кДж 

Answer 2

Calculation of Heat Required to Boil Water in the Iron Pot

To calculate the amount of heat required to boil the water in the iron pot, we can use the formula:

Q = m * c * ΔT

Where: - Q is the heat energy required (in joules) - m is the mass of the water (in kilograms) - c is the specific heat capacity of water (approximately 4200 J/kg·°C) - ΔT is the change in temperature (in °C)

Given: - Mass of the iron pot = 1.5 kg - Mass of the water = 2.5 kg - Initial temperature of the water = 20°C

To find the change in temperature, we need to know the boiling point of water. The boiling point of water at standard atmospheric pressure is 100°C.

Therefore, the change in temperature is:

ΔT = boiling point - initial temperature = 100°C - 20°C = 80°C

Now we can substitute the values into the formula:

Q = 2.5 kg * 4200 J/kg·°C * 80°C = 840,000 joules

Therefore, the amount of heat required to boil the water in the iron pot is 840,000 joules.