Question

определить энергию магнитного поля соленоида индуктивностью 1,4Гц по которуму течёт ток 3А.

Answer 1

Используешь одну формулу:
W=LI*2/2,где W-энергия маг.поля,I-сила тока,L-индуктивность
W=6,3Дж

Answer 2

W=L*I^2/2=1,4*9/2 = 6,3 Дж

Answer 3

Calculating the Energy of a Magnetic Field in a Solenoid

To calculate the energy of a magnetic field in a solenoid with an inductance of 1.4 H and a current of 3 A, we can use the formula for the energy stored in an inductor:

The energy stored in an inductor (W) is given by the formula: \[ W = \frac{1}{2} L I^2 \]

Where: - \( W \) = energy stored in the inductor (in joules) - \( L \) = inductance of the inductor (in henrys) - \( I \) = current flowing through the inductor (in amperes)

Calculation

Using the given values: - Inductance (\( L \)) = 1.4 H - Current (\( I \)) = 3 A

We can calculate the energy stored in the solenoid using the formula: \[ W = \frac{1}{2} \times 1.4 \times (3)^2 \]

\[ W = \frac{1}{2} \times 1.4 \times 9 \]

\[ W = 0.7 \times 9 \]

\[ W = 6.3 \, \text{joules} \]

So, the energy of the magnetic field in the solenoid with an inductance of 1.4 H and a current of 3 A is 6.3 joules.