Question

При обработке алюминиевой детали на станке,температура ее повысилась от 20 до420 градусов.На сколько при этом изменилась внутренняя энергия детали,если ее масса 500 г?

Answer 1

Дано: t1=20*, t2=420*, c=920Дж, m=0,5кг.
Си: -
Формула: E=cm(t2-t1)
Решение: E=920Дж*0,5кг(420-20)=184000Дж.
Ответ: 184000Дж.

Answer 2

Calculation of Change in Internal Energy

To calculate the change in internal energy of the aluminum part when its temperature increases from 20 to 420 degrees Celsius, we can use the equation:

ΔU = m * c * ΔT

Where: - ΔU is the change in internal energy - m is the mass of the aluminum part (500 g) - c is the specific heat capacity of aluminum - ΔT is the change in temperature (420 - 20 = 400 degrees Celsius)

Specific Heat Capacity of Aluminum

The specific heat capacity of a substance represents the amount of heat energy required to raise the temperature of a unit mass of the substance by one degree Celsius. The specific heat capacity of aluminum is approximately 0.897 J/g°C.

Calculation

Using the equation mentioned above, we can calculate the change in internal energy:

ΔU = m * c * ΔT

Substituting the given values: - m = 500 g - c = 0.897 J/g°C - ΔT = 400°C

ΔU = 500 g * 0.897 J/g°C * 400°C

Calculating the result:

ΔU = 179,400 J

Therefore, the change in internal energy of the aluminum part is 179,400 Joules when its temperature increases from 20 to 420 degrees Celsius.