Question

Мячик бросили с балкона вертикально вверх со скоростью 5 м/с. Через 2 с он упал на землю. С какой высоты его бросили?

Answer 1

Скорость шарика меняется при постоянном ускорении по закону: 
V(t)=V0-g*t, значит через время T=V0/g шарик достигнет максимальной высоты, а через время 
2T он вернется к балкону, имея скорость V0, направленную вниз. 
Теперь имеем: он будет двигаться вниз время 
t1 = t-2T = t-2*V0/g = (2-1) с = 1 с 
и пройдет путь 
H = V0*t1+g*t1^2/2 = (5 + 5) м = 10 м. 
(для простоты принял, что g=10 м/с^2).

Answer 2

Calculation of the Height

To determine the height from which the ball was thrown, we can use the equations of motion for vertical motion. The key equation is:

h = h0 + v0t - (1/2)gt^2

Where: - h is the final height (which we want to find) - h0 is the initial height (which is the height from which the ball was thrown, and we want to find) - v0 is the initial velocity (which is given as 5 m/s) - t is the time (which is given as 2 seconds) - g is the acceleration due to gravity (which is approximately 9.8 m/s^2)

Let's substitute the given values into the equation and solve for h:

h = h0 + (5 m/s)(2 s) - (1/2)(9.8 m/s^2)(2 s)^2

Simplifying the equation:

h = h0 + 10 m - 19.6 m

h = h0 - 9.6 m

Therefore, the height from which the ball was thrown is 9.6 meters.