Question

Сколько электронов прошло через поперечное сечение нити накаливания лампы,подключенной к напряжению 200 В ,если работа электрического поля равна 1 кДж.

Answer 1

A=IUt работа
q=It заряд
I сила тока
U напряжение
A=qU
q=Ne заряд равен  кол-во электронов умножить на заряд электрона
e=1.6*10(-19) Кл заряд электрона
 A=NeU
N=A/eU
N=1000/(200*1.6*10(-19))=3.125*10^19 (штук)

Answer 2

Необходимые формулы:
$A=q*U$
Найдем q
$q= \frac{A}{U}= \frac{1000}{200}=5$ Кл
Тогда
$N= \frac{q}{e}$
$N= \frac{q}{e}= \frac{5}{1,6*10^{-19}}= 3,125*10^{19}$

Ответ:
$N=3,125*10^{19}$

Answer 3

Calculating the Number of Electrons Passing Through the Filament Wire

To calculate the number of electrons that have passed through the cross-sectional area of the filament wire in the lamp, we can use the formula:

W = qV

Where: - W is the work done by the electric field (given as 1 kJ or 1000 J) - q is the charge (in coulombs) of the particles passing through the wire - V is the voltage (given as 200 V)

We can rearrange the formula to solve for q:

q = W / V

Substituting the given values: q = 1000 J / 200 V q = 5 C

Now, to find the number of electrons, we can use the elementary charge, which is the charge of a single electron: e = 1.6 x 10^-19 C

The number of electrons passing through the wire can be calculated using the formula: n = q / e

Substituting the values: n = 5 C / (1.6 x 10^-19 C) n ≈ 3.125 x 10^19 electrons

So, approximately 3.125 x 10^19 electrons have passed through the cross-sectional area of the filament wire in the lamp.