Question

тело массой 2кг двигалось со скоростью 5м/с и абсолютно неупруго столкнулось с таким же неподвижным телом.Новая скорость тел будет равна

Answer 1

Дано:

m=2 кг

v=5 м/c

Найти:

v'-?

Решение:

C-но ЗСИ:

mv=2mv'

отсюда

v'=0,5v

Ответ: 2,5 м/c

Answer 2

m1*u1=m2*u2= 2*5=5*u2

u2=m1*m2/m2=2*5/5=10/5=2м/c

Answer 3

Calculation of the new velocity after the collision

To calculate the new velocity of the two bodies after the collision, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

The momentum of an object is given by the product of its mass and velocity. Let's denote the mass of the two bodies as m1 and m2, and their initial velocities as v1 and v2, respectively.

Given: - Mass of each body (m1 = m2 = 2 kg) - Initial velocity of the first body (v1 = 5 m/s) - Initial velocity of the second body (v2 = 0 m/s)

Using the principle of conservation of momentum, we can write the equation:

m1 * v1 + m2 * v2 = m1 * v1' + m2 * v2'

where v1' and v2' are the new velocities of the first and second bodies after the collision, respectively.

Substituting the given values into the equation:

2 kg * 5 m/s + 2 kg * 0 m/s = 2 kg * v1' + 2 kg * v2'

Simplifying the equation:

10 kg m/s = 2 kg * v1' + 2 kg * v2'

Since the second body is initially at rest (v2 = 0 m/s), the equation becomes:

10 kg m/s = 2 kg * v1' + 0 kg m/s

Simplifying further:

10 kg m/s = 2 kg * v1'

Dividing both sides of the equation by 2 kg:

5 m/s = v1'

Therefore, the new velocity of the first body after the collision will be 5 m/s.

Since the second body is initially at rest, its new velocity after the collision will be 0 m/s.

Please note that this calculation assumes an idealized scenario of an elastic collision, where no energy is lost during the collision. In reality, collisions are often not perfectly elastic, and some energy may be lost as heat or sound.