Question

Автомобиль массой 2 т проходит по выпуклому мосту, имеющему радиус кривизны 40 м, со скоростью 36 км/ч (g=10 м/с²)

Answer 1

Дано:
m = 2 т = 2*10³ кг
R = 40 м
V = 36 км/ч = 10 м/с

N - ? 

Решение:

N = m(g-V²/R) = 2*10³ кг(10 м/с²-(10 м/с²)/40 м) = 1,5*10⁴ H или 15 кН 

Answer 2

Для решения данной задачи, нам необходимо учесть#### Calculating Centripetal Force on a Car Moving on a Curved Bridge

To calculate the centripetal force acting on a car of mass 2 tons moving on a curved bridge with a radius of curvature of 40 meters and a speed of 36 km/h, we can use the formula for centripetal force:

Centripetal force (F) = (mass of the car) × (velocity of the car)^2 / (radius of curvature)

Given: - Mass of the car = 2 tons = 2000 kg - Radius of curvature = 40 m - Speed of the car = 36 km/h

First, we need to convert the speed from km/h to m/s: - 36 km/h = 36 * (1000 m / 3600 s) = 10 m/s

Now, we can calculate the centripetal force using the given values: - Centripetal force (F) = (2000 kg) × (10 m/s)^2 / 40 m

Calculating: - F = (2000) × (100) / 40 - F = 5000 N

So, the centripetal force acting on the car is 5000 N.